Question 1001764
can do this by 8 choose 6 with the given probabilities of 58% and 42%
also can do it by knowing order doesn't matter, and one form of the 28 ways can choose 6 from 8 8!/6!2!
the six might be the first six
29/50 *28/49*27/48*26/47*25/46*24/44*21/43*20/42.
The denominator stays the same for all 28 ways.  The numerator is the same, too, but it is multiplied in a different order.
28(0.58^6)(0.42)^2=0.188029
8(0.58^7)(0.42)=0.074188 because there are only 8 ways to choose 7.
(0.58^8)=0.012806
The total is 0.275023
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at least 2 are males
do 0,1, and subtract from 1
p(0)=p(8 females)=0.012806
p(1)=p(7 females)=0.074188
They add to 0.086994
subtract from 1, because we don't want these, and get 0.913006.