Question 1001734
The SE is s/sqrt(n)=1234.5
n=100 is large enough to use the z-distribution, and z(0.95)-1.96
1.96*SE=2419.62,  That is the half-width of the CI and the margin of error when said +/-.
(9500-2419.6, 9500+2419.6)
(7080.4, 11919.6)