Question 1001748
From {{{(4n^2-8n+3)/(2n^3-3n^2)}}}
let us factor and cancel...
we get (2n-3)(2n-1) on the top and
(2n-3)(n^2) on the bottom...
Cancel out the 2n-3 and get
{{{(2n-1)/(n^2)}}}