Question 1001661
{{{f(x)=(x-4)^3-4(x-4)}}}
From here, x=4 would make the function equal 0.  Degree 3 for x in the function definition.  It appears to be the only zero for the function, or at least the only real zerol


{{{f(x)=(x-4)((x-4)^2-4)}}}


Do the full multiplying to get general form, and it is  {{{x^3-12x^2+44x-48}}}.


Test the root of 4 using synthetic division, and the resulting quotient is  {{{x^2-8x+12}}} which is factorable...


The fully factorized function is therefore  {{{highlight((x-4)(x-6)(x-2))}}}.  The roots or zeros are  4, 6, and 2, each of  multiplicity ONE.