Question 1001377
Let the width of sidewalk be x																
..																
Length of garden =			12	m  												
Width =			9	m  						315.64						
																
Area =			108		m^2											
Area of sidewalk =			46	m^2												
Length of ground + sidewalk =							12	+	2	x 						
width of ground + sidewalk =				9	+	2	x									
																
(	12	+	2	x	)	(	9	+	2	x	)	+	-108	=	46	
																
	108	+	24	x	+	18	x	+	4	X^2		+	-108	=	46	
	4	X^2		+	42	x	+	-46	=	0						
	Find the roots of the equation by quadratic formula															
	a=	4	b=	42	c=	-46										
	b^2-4ac=	1764	-	-736												
	b^2-4ac=	2500			{{{sqrt(	2500	)}}}=	50								
	{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}															
	{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}															
	x1=(	-42	+	50	)/	8										
	x1=	1														
	x2=(	-42	-50	) /	8											
	x2=	-15.5														
	Ignore negative value															
	width of sidewalk =		1	m