Question 1001291
ax^3+bx^2+cx+d=f(x)
when x=0, f(x)=2
a= -2
d=2
-2x^3+bx^2+cx+2=f(x)
f(1)=1
so -2+b-c+2=1
b+c=1
f(-2)= -2
16+4b-2c+2= -2
4b-2c=-20
b+c=1
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4b-2c= -20
2b+2c=2
6b=-18
b=-3
c=4
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-2x^3-3x^2+4x+2=f(x); f(1)=1; f(-2)=-2, f(-1)= -3  ANSWER
{{{graph(300,200,-10,10,-10,10,-2x^3-3x^2+4x+2)}}}