Question 1001254
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Given a quadratic function in standard form, *[tex \Large \rho(x)\ =\ ax^2\ +\ bx\ +\ c]


The *[tex \Large x]-coordinate of the vertex is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x_v = \frac{-b}{2a}]


The *[tex \Large y]-coordinate of the vertex is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y_v = f(x_v) = f\left(\frac{-b}{2a}\right)]


The equation of the axis of symmetry is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ x_v]


The domain of all polynomial functions regardless of degree is the set of all real numbers.


If *[tex \Large a\ >\ 0] then the range is *[tex \Large y_v\ \leq\ \rho(x)\ <\  \infty]


If *[tex \Large a\ <\ 0] then the range is *[tex \Large -\infty\ <\ \rho(x)\ \leq\ y_v ]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \