Question 1001267
From 3y+x=3, let's put it into slope-intercept form to find the slope...
3y = -x + 3
y (-1/3)x + 1
So if we need a perpendicular line it is the negative reciprocal of (-1/3).
That would be 3.
Now plug that and the point (6,-1) into y = mx + b to find b:
-1 = 3(6) + b
-1 = 18 + b
b = -19
and
y = 3x - 19