Question 1001102
Let's call the 5 x and the 20 z:
x+z= 28. If we subtract z from both sides we get:
x= 28-z Let's use this value for x in the next equation:
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5(28-z)+20z= 350
140-5z+20z= 350 Subtract 140 on both sides and add on left:
15z= 210
z= 210/15
z= 14 he has 14 $5 bills
And how many $20 bills+ 28-14
J