Question 1000991


1. Given {{{f(x)=3x+8}}}  and {{{g(x)=6x+6}}}

 then what is {{{(f-g)(-1)}}} ?

{{{(f-g)(x)=3x+8-(6x+6)}}}
{{{(f-g)(x)=3x+8-6x-6}}}
{{{(f-g)(x)=-3x+2}}}

then,
{{{(f-g)(-1)=-3(-1)+2}}}
{{{(f-g)(-1)=3+2}}}
{{{(f-g)(-1)=5}}}


2. Simplify the radicals

{{{sqrt(192) + sqrt(80) + sqrt(12288)=sqrt(64*3) + sqrt(16*5) + sqrt(64*64*3)=8sqrt(3) + 4sqrt(5) + 64sqrt(3)=72sqrt(3) + 4sqrt(5)}}}


so, (A,B)= (72,4)


3. Solve the following radical equation {{{sqrt(2x+3)=13}}}... guess you have that
{{{sqrt(2x+3)=13}}}
{{{(sqrt(2x+3))^2=13^2}}}
{{{2x+3=169}}}
{{{2x=169-3}}}
{{{2x=166}}}
{{{x=166/2}}}
{{{x=83}}}

answer is:
a. {{{x = 83}}}