Question 85541
Use the simplex method to solve the linear programming problem: 
minimize: W= 4y1+2y2
Subject to:
3y1+2y2>=60
4y1+y2>=40
y1>=0,y2>=0
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Draw a y1-y2 coordinate system; let y2 be the horizontal axis.
Graph y1 >=(-2/3)y2+20

Graph y1 >=(-1/4)y2+10
Graph y1>=0
{{{graph(400,300,-5,40,-5,30,(-2/3)x+20,(-1/4)x+10)}}}
Graph y2>=0
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Find all the intersection points of the EQUALITY statements.
These are (0,10), (0,20) and (24,4)
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Evaluate w = 4y1 + 2y2 for each of the intersection coordinate pairs.
For (0,10) you get w = 20
For (0,20) you get w = 40
For (24,4) you get 4*24+2*4 = 104
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Select the coordinate pair that gives you the minimum w value as your solution
That would be y1=0, y2=10.
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Cheers,
Stan H.