Question 1000756
Since this one is tall, not wide, the distance to the focus (from the origin) will be found by
{{{c^2=b^2-a^2}}}
{{{c^2=64-9}}}
{{{c^2=55}}}
{{{c=sqrt(55)}}}
and the points are
(0, sqrt(55)) and (0, -sqrt(55))