Question 1000662
Given that z is a standard normal random variable, compute the following probabilities. 
a. P(z≤ -1) = normalcdf(-100,-1) = 0.1587
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b. P(z≥ -1) = = 1 - 0.1587 = 0.8413
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c. P(z≥ -1.5) = normalcdf(-1.5,100) = 0.9332
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d. P(-3≤z≤0) = normalcdf(-3,0) = 0.4987
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Cheers,
Stan H.
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