Question 12177
Juan has 15 pennies
subtract 15 coins from 51
51-15=36 remaining coins


8 more nickles than dimes
dimes=x
nickles=x+8


the sum of the number of dimes and the number of nickles= 36
x+(x+8)=36
2x+8=36           <--subtract 8 from both sides
(2x+8)-8=36-8
2x=28        <--divide both sides by 2
{{{2x/2}}}={{{28/2}}}
x=14


if dimes=x and x=14, he has 14 dimes
nickles=x+8=14+8=22 nickles




he has 14 dimes




Check:  14+22+15=51