Question 1000326
g(x) would be expected to be not a linear function.


(a) point is here now moved to the right by 1 unit and not moved up or down.
This gives {{{g(x-1)+0}}} to define the new function.


(b) point is now moved from g(x), only upward by 2 units, so it is  {{{g(x)+2}}} as the new function's definition.