Question 999726
 find the values, given the following equations:
f(x)=3x^2-2x-4 and g(x)=3x-4
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a. f(0) = -4
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b. f(x+3) = 3(x+3)^2-2(x+3)-4 = 3(x^2+6x+9)-2x-6-4 = 3x^2 +16x + 17
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c. f(x)+g(x) = 3x^2 + x - 8
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d. f(g(x)) = f[3x-4] = 3(3x-4)^2 - 2(3x-4) - 4 
= 3[9x^2 -24x + 16) -6x + 8 -4
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= 27x^2 - 72x + 48 - 6x + 4
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= 27x^2 - 78x + 52
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Cheers,
Stan H.
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