Question 1000305
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1.  ln(AB) = ln(A) + ln(B) = x + y.


     First equality is the basic property of the logarithm.  Are you familiar with it?


     The second equality is true because  ln(A) = x  and  ln(B) = y,  which is given.  I simply made a substitution here.



2.  ln(A)/ln(B) = {{{x/y}}}.


     Simply substitute  x  and  y  instead of  ln(A)  and  ln(B)  into the numerator and denominator. 



3.  {{{A*B}}} = {{{e^x}}} . {{{e^y}}}.


     Since  {{{ln(A)}}} = {{{x}}},  you have  {{{A}}} = {{{e^x}}}.


     Since  {{{ln(B)}}} = {{{y}}},  you have  {{{B}}} = {{{e^y}}}.


     Then substitute this into  {{{A*B}}}.



That is all,  my dear.


Look into my lessons 

&nbsp;&nbsp;&nbsp;&nbsp;- <A  HREF=http://www.algebra.com/algebra/homework/logarithm/what-is-the-logarithm.lesson>WHAT IS the logarithm</A>&nbsp; 

&nbsp;&nbsp;&nbsp;&nbsp;- <A  HREF=http://www.algebra.com/algebra/homework/logarithm/Properties-of-the-logarithm.lesson>Properties of the logarithm</A> 

in this site.


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