Question 1000186

First Equation
{{{x/3+y/2=-4}}}
{{{y/2=-x/3-4}}}
{{{y=-(2/3)x-12}}}


Second Equation
{{{x-3y=6}}}
{{{-3y=-x+6}}}
{{{y=x/3-2}}}


The system should be solvable.
Both formulas for y can be shown equated to find a solution.
{{{highlight_green(-(2/3)x-12=x/3-2)}}}----equating the two y expressions
{{{-(2/3)x-12-(1/3)x=-2}}}
{{{-x-12=-2}}}
{{{x+12=-2}}}
{{{highlight(x=-14)}}}


Using the y equivalent of the second equation:
{{{y=x/3-2}}}
{{{y=14/3-2}}}
{{{y=14/3-6/3}}}
{{{highlight(y=8/3)}}}