<PRE><B>Question 1000133</B>
 How much 50% antifreeze solution and 40% antifreeze solution should be combined to give 50 gallons of 46% antifreeze solution? 
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Equation:
active + active = active
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0.50x + 0.40(50-x) = 0.46*50
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50x + 40*50 - 40x = 46*50
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10x = 6*50
x = 30 gallons (amt. of 50% solution needed)
50-x = 20 gallons (amt. of 40% solution needed)
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Cheers,
Stan H.
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