Question 1000020
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Please help me with this problem of proof, given: BD parralel to AC, D is the midpoint of AC 
Prove: BC ≈ BA
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Hello,


if BD parallel to AC and D lies on AC, then the straight line BD coincide with AC.


Therefore, your formulation is defective. 


Think what really you want to prove.Then re-formulate and re-submit.


Beside of it, we don't know what does it mean this symbol "≈".