Question 85515
4^(3x)=7^(x+1)
Since the variables are in the exponent, take the log of both sides to get:
(3x)log4 = (x+1)log7
(3log4)x = (log7)x + log7
(3log4-log7)x = log7
log[(4^3)/7]x = log7
0.961081934x = 0.84509804
x=0.8793194525...
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Cheers,
Stan H.