Question 999894
f(x)=4x^2-16x+30
x=(1/8)(16+/- sqrt (256-480).  The square root is negative.  There are no zeros.
{{{graph(300,200,-10,100,-10,100,4x^2-16x+30)}}}


x(x-3)&#12311;^2 &#12310;(x+1)&#12311;^4 
Either of the two must equal zero
x=0, x=3, x=-1