Question 999861
Perpendicular lines have slopes that are negative reciprocals.
{{{m[1]*m[2]=-1}}}
{{{2*m[2]=-1}}}
{{{m[2]=-1/2}}}
Then using the point slope form of a line,
{{{y-(-3)=-(1/2)(x-2)}}}
{{{y+3=-(1/2)x+1}}}
{{{y=-(1/2)x-2}}}
.
.
.
*[illustration ds1.JPG].