Question 85501
 A pharmacist has 1 liter of a solution that is 22% alcohol. How much pure alcohol must be added to bring the solution up to 27% alcohol
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Let x = the amt of pure alcohol to be added;
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Then the final amt  = (x + 1)
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Write a per cent equation:
100% (pure) alcohol is 1.0(x)
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.22(1) + 1.0(x) = .27(x+ 1)
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.22 + x = .27x + .27
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x - .27x = .27 - .22
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.73x = .05
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x = .05/.73
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x = .068 liters of pure alcohol required to get a 27% solution
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Check our answer: resulting amt would be 1.068:
.22 + .068 = .27(1.068)
.288 = .288; proves our solution
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