Question 999807
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ ax^2\ +\ bx\ +\ c]


so if (0,4) is an element of the solution set, then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4\ =\ a(0)^2\ +\ b(0)\ +\ c]


Which is to say *[tex \Large c\ =\ 4]


Then if (2, 20) is an element of the solution set, then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 20\ =\ a(2)^2\ +\ b(2)\ +\ 4]


Which is to say *[tex \Large 4a\ +\ 2b\ =\ 16]


Then if (10,4) is an element of the solution set, then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4\ =\ a(10)^2\ +\ b(10)\ +\ 4]


Which is to say *[tex \LARGE 100a\ +\ 10b\ =\ 0]


Solve the 2X2 system of linear equations to find the coefficients *[tex \Large a] and *[tex \Large b].  Then, when you have your fully-qualified polynomial, you can evaluate *[tex \Large y(3)] to find *[tex \Large m]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \