Question 999789
{{{5x^2y^2}}} is factored from the term {{{20x^4y^10}}}

to find what term remains, divide {{{20x^4y^10}}} by {{{5x^2y^2}}}

{{{(20x^4y^10)/(5x^2y^2)}}}

{{{(cross(20)4x^cross(4)^2y^cross(10)^8)/(cross(5)1cross(x^2)1cross(y^2)1)}}}

{{{4x^2y^8}}}

so, answer is: C){{{4x^2y^8}}}