Question 999766
{{{2x+4+y=0}}}....here you have a linear function and its graph is a line

to graph a line you need two points that lie on a line

so, choose x-intercept and y-intercept; that is easiest way to find two points that lie on a line

x-intercept is at ({{{x}}},{{{0}}})
so, set {{{y=0}}} and solve for {{{x}}}

{{{2x+4+0=0}}}

{{{2x+4=0}}}

{{{2x=-4}}}

{{{x=-4/2}}}

{{{x=-2}}}


x-intercept is at ({{{-2}}},{{{0}}})

now find

y-intercept which is at ({{{0}}},{{{y}}})

so, set {{{x=0}}} and solve for {{{y}}}

{{{2*0+4+y=0}}}

{{{4+y=0}}}

{{{y=-4}}}


y-intercept is at ({{{0}}},{{{-4}}})


now, plot these points and draw a line through:


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(0,-4,.12),circle(-2,0,.12),
locate(0.3,-3.8,p(0,-4)),locate(-2,0.6,p(-2,0)),
 graph( 600, 600, -10, 10, -10, 10, -2x-4)) }}}