Question 999742
Determine the cubic equation that has zeros at 4,3 and -2, if f(2)=-4.
Work I have done so far:
Factors:: x-4, x-3, x+2
Equation: y = a(x-4)(x-3)(x+2)
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Solve for "a" using (2,-4)
-4 = a(-2)(-1)(4)
a = -4/8
a = -1/2
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Equation:
y = (-1/2)(x-4)(x_3)(x+2)
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Cheers,
Stan H.
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