Question 999717
Find a cubic polynomial in standard form with real coefficients, having the zeros 2 and 6i. Let the leading coefficient be 1
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If 6i is a zero then -6i is too.
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--> (x-2)*(x-6i)*(x+6i)
= {{{(x-2)*(x^2 + 36)}}}
= {{{x^3 - 2x^2 + 36x - 72}}}