Question 999646
you just need the coordinates of two points that lie one line to find the equation of that line

{{{y=mx+b}}}

use y-intercept which is at ({{{0}}},{{{0}}}); at origin

so, we already know {{{b}}}: {{{b=0}}}

{{{y=mx}}}

to find a slope, use   ({{{0}}},{{{0}}}) and the point  ({{{2}}},{{{3}}}) which also lie on a line

{{{m=(y[2]-y[1])/(x[2]-x[1])=(3-0)/(2-0)=3/32}}}

then, your equation is:

{{{y= (3/2)x}}}


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(0,0,.12),circle(2,3,.12),
locate(0.3,0,p(0,0)),locate(2,3,p(2,3)),
 graph( 600, 600, -10, 10, -10, 10, (3/2)x)) }}}