Question 999630
here's the picture of your graph.


<img src = "http://172.85.76.57/Library/00001230_84_624_A1.png" alt="$$$" </>


from what i can see, the graph crosses the y-axis at (0,1) and it crosses the x-axis at (1.5,0)


the slope is the change in y divided by the change in x.


the formula for that is (y2-y1) / (x2-x1).


if you let (x1,y1) = 0,1) and you let (x2,y2) = (1.5,0), then:


(y2-y1) / (x2-x1) becomes (0-1) / (1.5-0) which becomes -1 / 1.5 which becomes -2 / 3 if you need to have a simplified version where both numerator and denominator are integers.


-2/3 was derived by multiplying -1/1.5 * 2/2.


the y-intercept is the value of y when x is equal to 0.


since one of your points is at (0,1) which means the value of y when x = 0, your y-intercept is already shown at y = 1.


the slope intercept form of the equation for a straight line is y = mx + b.


m is the slope and b is the y-intercept.


the equation of your line is therefore y = -2/3 * x + 1


when x = 0, the value of y is -2/3 * 0 + 1 which is equal to 1.


when x = 1.5, the value of y is -2/3 * 1.5 + 1 which is equal to -3/3 + 1 which is equal to -1 + 1 which is equal to 0.


these two points of (0,1) and (1.3,0) are the same two points you show on the graph you supplied, as best i can determine.


here's a graph of that equation.


<img src = "http://theo.x10hosting.com/2015/102803.jpg" alt="$$$" </>


if i got the points correctly, the equation is y = -2/3 * x + 1