Question 999419
First find the slope of the line.
{{{m=(-5-(-3))/(-2-(-1))=(-2)/(-1)=2}}}
Perpendicular lines have slopes that are negative reciprocals so,
{{{2*m[2]=-1}}}
{{{m[2]=-1/2}}}
Then using the point-slope form,
{{{y-5=-(1/2)(x-3)}}}
{{{y-5=-(1/2)x+3/2}}}
{{{y=-(1/2)x+3/2+10/2}}}
{{{y=-(1/2)x+13/2}}}
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