<PRE><B>Question 999539</B>
It says to solve each system by substitution and elimination but I don&#39;t understand on how to do it.
Y=-3x+4
Y=3x-2
&lt;pre&gt;&lt;b&gt;&lt;u&gt;ELIMINATION&lt;/b&gt;&lt;/u&gt;
y = - 3x + 4 --- eq (i)
y = 3x - 2 ----- eq (ii)
2y = 2 --------- Adding eqs (ii) &amp; (i)
y = {{{2/2}}}, or {{{highlight_green(1)}}}
1 = - 3x + 4  ------- Substituting 1 for y in eq (i)
3x = 4 - 1
3x = 3
x = {{{3/3}}}, or {{{highlight_green(x = 1)}}}
&lt;b&gt;&lt;u&gt;SUBSTITUTION&lt;/b&gt;&lt;/u&gt;
Since both equations have already been solved for y, then just set them equal to each other, as follows: - 3x + 4 = 3x - 2
Solve this for x, then find y</PRE>