Question 999517

solve each system of equations by the substitution method
3y-x=6
4x+12y=0
<pre>3y - x = 6______3y - 6 = x -------- eq (i)
4x + 12y = 0 ------- eq (ii)
4(3y - 6) + 12y = 0 ------ Substituting 3y - 6 for x in eq (ii)
12y - 24 + 12y = 0
12y + 12y = 24
24y = 24
y = {{{24/24}}}, or {{{highlight_green(y = 1)}}}
3(1) - 6 = x ------ Substituting 1 for y in eq (i) 
3 - 6 = x
{{{highlight_green(- 3 = x)}}}