Question 999385
Given the above operation,
a*(a*2) = 10
a*(a+2-2a)=10
a*(2-a)=10
a+(2-a)-a(2-a) = 10
2 - 2a + a^2 = 10
a^2 - 2a - 8 = 0
(a-4)(a+2)=0
a = 4 and a = -2