Question 999197
Hi there,
h(x) = 16x - x^2.
A) For what value of X will the Archway be 28 feet above the water?
28 = 16x - x^2
Multiply through by -1
x^2 - 16x + 28 = 0
(x - 2)(x - 14) = 0
x = 2 and x = 14
B) How wide is the Archway At the water?
16x - x^2 = 0
x(16 - x) = 0
x = 0 and x = 16
Width = 16 ft
C)What is the maximum height of the arch?
Mid point x = 8
h(x) = 16(8) - 8^2
h(x) = 128 - 64
Height = 64 ft.
Hope this helps :-)