Question 999214

 If ({{{x}}},{{{-12}}}) is a solution to the equation {{{y= -(1/3)x-2}}}, than the value of {{{x}}} will be:

{{{-12= -(1/3)x-2}}}

{{{-12+2= -(1/3)x}}}

{{{-10= -(1/3)x}}}

{{{-10*(-3)=(-cross(3)) -(1/cross(3))x}}}

{{{30=x}}}