Question 997929
So find the probability for the three possible hands.
5 drawn on first draw, not 5 on the second.{{{P[1]=(4/52)(48/51)}}}
5 drawn on second draw, not 5 on the first.{{{P[2]=(48/52)(4/51)}}}
5 drawn on first draw, 5 drawn on the second.{{{P[3]=(4/52)(3/51)}}}
{{{P=P[1]+P[2]+P[3]}}}
{{{P=192/2652+192/2652+12/2652}}}
{{{P=396/2652}}}
{{{P=33/221}}}