Question 997846
By any, I'm assuming you mean one set.
{{{A=1}}}
{{{B=1}}}
So then,
{{{x+y=C}}}
{{{2-1=1}}}
{{{C=1}}}
.
.
{{{D=-1}}}
{{{E=-1}}}
{{{-x-y=F}}}
{{{-2-(-1)=F}}}
{{{F=-1}}}