Question 999093
{{{ (csc(b)tan(b))/sec(b) }}}......since {{{csc(b)=1/sin(b)}}}, {{{tan(b)=sin(b)/cos(b)}}} and  {{{sec(b)=1/cos(b) }}}, we have


={{{ ((1/sin(b))(sin(b)/cos(b)))/(1/cos(b)) }}}


={{{ ((1/cross(sin(b))1)(cross(sin(b))1/cos(b)))/(1/cos(b)) }}}


={{{ (1/cos(b))/(1/cos(b)) }}}


={{{ cos(b)/cos(b) }}}


={{{ 1}}}