Question 999082
A manufacturer claims that at least 95% of the equipment that she supplied to a
factory conformed to the specification. An examination of a sample of 200 pieces
of equipment revealed 18 were faulty. Test for her claim at levels of significance 
(a) 0.01
Ho: p >= 0.95 (claim)
Ha: p < 0.95
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p-hat = 182/200 = 0.91
z(0.41) = (0.91-0.95)/sqrt[0.95*0.05/200] = -0.04/sqrt[0.95*0.05/200] 
= -2.5955
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p-value = P(z < -2.5955) = 0.0047
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Conclusion: Since the p-value is less than 1%, reject Ho ; reject the claim.
 
(b) 0.05
Conclusion:: Since the p-value is less than 5%, reject Ho ; reject the claim.
Cheers,
Stan H.