Question 999071
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4x + 4y = 8   (1)
2x +  y = 2   (2)

Multiply the equation (2) by 2 (both sides). You will get

4x + 4y = 8   (1')
4x + 2y = 4   (2')

Distract (2') from (1') (both sides). You will get

(4x - 4x) + (4y - 2y) = 8 - 4, or

0*x + 2y = 4, or

2y = 4.

Hence, y = {{{4/2}}} = 2.

Now you can easily find x from 4x + 4y = 8. 

Namely, 4x = 8 - 4y = 8 - 4*2 = 0, hence, x = 0.

<U>Answer</U>. x=0, y=2
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