Question 998952
we have the i component given as 16 and the magnitude of the two components is 20.6, therefore the cosine of x is 
cos x = 16 / 20.6 = 0.776699029
now we want the cosine inverse of 0.776699029 to find the bearing
cos^(-1) 0.776699029 = 39.04 degrees
note that bearing is measured from the positive x axis