Question 998854


{{{3x^2-4x-7=0}}}..........factor completely

{{{3x^2+3x-7x-7=0}}}

{{{(3x^2+3x)-(7x+7)=0}}}

{{{3x(x+1)-7(x+1)=0}}}

{{{(x+1)(3x-7) = 0}}}

roots:

if {{{(x+1) = 0}}}=>{{{x=-1}}}
if {{{(3x-7) = 0}}}=>{{{x=7/3}}}


reciprocal of {{{x=-1}}} is {{{x=1/-1=-1}}}

reciprocal of {{{x=7/3}}} is {{{x=1/(7/3)=3/7}}}

their sum is:{{{-1+3/7=-7/7+3/7=-4/7}}}