<PRE><B>Question 998824</B>
a) 3^2x + 35 = 12(3^x)
(3^x)^2-36*3^x + 35 = 0
(3^x-35)(3^x-1)=0 
3^x = 35 of 3^x = 1
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x = log(35)/log(3) or x = log(1)/log(3)
x = 1.8654 or x = 0
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b) I was not sure how to do this one
2(lnx)^2 + 9 lnx - 5 = 0
(2ln(x)-1)(2ln(x)+5) = 0
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ln(x) = 1/2 or ln(x) = -5/2
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x = e^(1/2) or x = e^(-5/2)
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Cheers,
Stan H.
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