<PRE><B>Question 998766</B>
Mean of First term of an AP is 27

Sum = 5*27 = 135

S5= 135

similarly S8 = 39*8= 312

135 = 5/2( 2a+(5-1)d)

270=5( 2a+4d)

54 =2a+4d
/2
27= a+2d..........(1)

sum of eighth term 

312 = 8/2(2a+(8-1)d)

78 = 2a+7d..........(2)

solve (1) &amp; (2)
we get d=8

and a = 11

I term = 11

difference =8


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