Question 998758


{{{log(sqrt(2),8sqrt(2))= 7}}}......change the base to base {{{10}}}

{{{log(8sqrt(2))/log(sqrt(2))= 7}}}

{{{log(8sqrt(2))= 7log(sqrt(2))}}}

{{{log(8sqrt(2))= log((sqrt(2))^7)}}}...if log same, than

{{{8sqrt(2)= (sqrt(2))^7}}}

{{{8sqrt(2)= (sqrt(2))^2*(sqrt(2))^2*(sqrt(2))^2*sqrt(2)}}}

{{{8sqrt(2)= 2*2*2*sqrt(2)}}}

{{{8sqrt(2)= 8sqrt(2)}}}...since left and right side of equation sign are same, the statement {{{log(sqrt(2),8sqrt(2))= 7}}} is true