Question 998742
Put these in slope intercept form and if the slopes are equal, they are parallel, and if they are negative reciprocals, they are perpendicular.
-2y=-x+6
y=(1/2)x-6
y=-2x-3.  These are perpendicular.
{{{graph(300,200,-10,10,-7,7,(x/2)-6,-2x-3)}}}
-y=-3x+1
y=3x-1
3y-x=3
y=(x/3)+3
Neither.
{{{graph(300,200,-10,10,-7,7,3x-1,(x/3)+3)}}}