Question 998702
log(base2)(x^2)-log(base2)(x+4)=2


{{{log(2,(x^2))-log(2,(x+4))=2}}}


{{{log(2,(x^2/(x+4)))=2}}}
Base of the exponent AND the logarithm both are 2.
Put into exponential form.


{{{2^2=x^2/(x+4)}}} 


{{{x^2=4(x+4)}}}
{{{x^2=4x+16}}}
{{{x^2-4x-16=0}}}
{{{x=(4+- sqrt(16+4*16))/2}}}
{{{x=(4+- 4sqrt(1+4))/2}}}
{{{highlight(x=2+- 2sqrt(5))}}}