Question 998644


{{{x^2-8x+16=0}}}

{{{x^2-4x-4x+16=0}}}


x(x-4)-x(x-4)=0

(x-4)(x-4)=0

x-4 =0

x=4

{{{x^2+14x=0}}}

{{{x(x+14)=0}}}

x= 0 OR

x_14=0
x=-14

0,-14



{{{6x^2-7x+3=0}}}

{{{6x^2-9x+2x-3=0}}}

3x(2x-3)+1(2x-3)=0

(3x+1)(2x-3)=0

3x+1=0 OR 2x-3=0

3x+1=0
x= -1/3

2x-3=0

x= 3/2